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Solve 5x āˆ’ 3 = 42

The solution of 5x āˆ’ 3 = 42 is x = 9.

The lines y = 5x āˆ’ 3 and y = 42 meet at x = 946810121410203040506070x = 9y = 5x āˆ’ 3y = 42
The lines y = 5x āˆ’ 3 and y = 42 meet at x = 9. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    5xāˆ’3=425x - 3 = 42
  2. 2

    Add 3 to both sides:

    5xāˆ’3+3=42+3 ⇒ 5x=455x - 3 + 3 = 42 + 3 \ \Rightarrow\ 5x = 45
  3. 3

    Divide both sides by 5:

    5x5=455 ⇒ x=9\frac{5x}{5} = \frac{45}{5} \ \Rightarrow\ x = 9
  4. 4

    Check: put x = 9 back into the equation.

    5ā‹…9āˆ’3=45āˆ’3=42āœ“5\cdot9 - 3 = 45 - 3 = 42 \checkmark
LaTeX source of the formulas on this page
\[ 5x - 3 = 42\ \Rightarrow\ x = 9 \]
\[ 5x - 3 = 42 \]
\[ 5x - 3 + 3 = 42 + 3 \ \Rightarrow\ 5x = 45 \]
\[ \frac{5x}{5} = \frac{45}{5} \ \Rightarrow\ x = 9 \]
\[ 5\cdot9 - 3 = 45 - 3 = 42 \checkmark \]

Trying values of x in 5x āˆ’ 3 = 42

x5x āˆ’ 3Equals 42?
732no
837no
942yes
1047no
1152no

Questions

What is x in 5x āˆ’ 3 = 42?

The solution of 5x āˆ’ 3 = 42 is x = 9.

How do you solve 5x āˆ’ 3 = 42?

Add 3 to both sides to get 5x = 45, then divide both sides by 5 to get x = 9.

How do I check the answer?

Replace x by 9: 5(9) āˆ’ 3 = 42, which is 42.

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