Solve 5x ā 2 = ā27
The solution of 5x ā 2 = ā27 is x = -5.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 2 to both sides:
- 3
Divide both sides by 5:
- 4
Check: put x = -5 back into the equation.
LaTeX source of the formulas on this page
\[ 5x - 2 = -27\ \Rightarrow\ x = -5 \]
\[ 5x - 2 = -27 \]
\[ 5x - 2 + 2 = -27 + 2 \ \Rightarrow\ 5x = -25 \]
\[ \frac{5x}{5} = \frac{-25}{5} \ \Rightarrow\ x = -5 \]
\[ 5\cdot(-5) - 2 = -25 - 2 = -27 \checkmark \]Trying values of x in 5x ā 2 = ā27
| x | 5x ā 2 | Equals -27? |
|---|---|---|
| -7 | -37 | no |
| -6 | -32 | no |
| -5 | -27 | yes |
| -4 | -22 | no |
| -3 | -17 | no |
Questions
What is x in 5x ā 2 = ā27?
The solution of 5x ā 2 = ā27 is x = -5.
How do you solve 5x ā 2 = ā27?
Add 2 to both sides to get 5x = -25, then divide both sides by 5 to get x = -5.
How do I check the answer?
Replace x by -5: 5(-5) ā 2 = -27, which is -27.