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Solve 5x āˆ’ 12 = āˆ’32

The solution of 5x āˆ’ 12 = āˆ’32 is x = -4.

The lines y = 5x āˆ’ 12 and y = -32 meet at x = -4-10-8-6-4-22-60-50-40-30-20-10x = -4y = 5x āˆ’ 12y = -32
The lines y = 5x āˆ’ 12 and y = -32 meet at x = -4. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    5xāˆ’12=āˆ’325x - 12 = -32
  2. 2

    Add 12 to both sides:

    5xāˆ’12+12=āˆ’32+12 ⇒ 5x=āˆ’205x - 12 + 12 = -32 + 12 \ \Rightarrow\ 5x = -20
  3. 3

    Divide both sides by 5:

    5x5=āˆ’205 ⇒ x=āˆ’4\frac{5x}{5} = \frac{-20}{5} \ \Rightarrow\ x = -4
  4. 4

    Check: put x = -4 back into the equation.

    5ā‹…(āˆ’4)āˆ’12=āˆ’20āˆ’12=āˆ’32āœ“5\cdot(-4) - 12 = -20 - 12 = -32 \checkmark
LaTeX source of the formulas on this page
\[ 5x - 12 = -32\ \Rightarrow\ x = -4 \]
\[ 5x - 12 = -32 \]
\[ 5x - 12 + 12 = -32 + 12 \ \Rightarrow\ 5x = -20 \]
\[ \frac{5x}{5} = \frac{-20}{5} \ \Rightarrow\ x = -4 \]
\[ 5\cdot(-4) - 12 = -20 - 12 = -32 \checkmark \]

Trying values of x in 5x āˆ’ 12 = āˆ’32

x5x āˆ’ 12Equals -32?
-6-42no
-5-37no
-4-32yes
-3-27no
-2-22no

Questions

What is x in 5x āˆ’ 12 = āˆ’32?

The solution of 5x āˆ’ 12 = āˆ’32 is x = -4.

How do you solve 5x āˆ’ 12 = āˆ’32?

Add 12 to both sides to get 5x = -20, then divide both sides by 5 to get x = -4.

How do I check the answer?

Replace x by -4: 5(-4) āˆ’ 12 = -32, which is -32.

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    Solve 5x āˆ’ 12 = āˆ’32: x = -4 (steps and check) | WordGPT