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Solve 5x āˆ’ 12 = 28

The solution of 5x āˆ’ 12 = 28 is x = 8.

The lines y = 5x āˆ’ 12 and y = 28 meet at x = 82468101214102030405060x = 8y = 5x āˆ’ 12y = 28
The lines y = 5x āˆ’ 12 and y = 28 meet at x = 8. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    5xāˆ’12=285x - 12 = 28
  2. 2

    Add 12 to both sides:

    5xāˆ’12+12=28+12 ⇒ 5x=405x - 12 + 12 = 28 + 12 \ \Rightarrow\ 5x = 40
  3. 3

    Divide both sides by 5:

    5x5=405 ⇒ x=8\frac{5x}{5} = \frac{40}{5} \ \Rightarrow\ x = 8
  4. 4

    Check: put x = 8 back into the equation.

    5ā‹…8āˆ’12=40āˆ’12=28āœ“5\cdot8 - 12 = 40 - 12 = 28 \checkmark
LaTeX source of the formulas on this page
\[ 5x - 12 = 28\ \Rightarrow\ x = 8 \]
\[ 5x - 12 = 28 \]
\[ 5x - 12 + 12 = 28 + 12 \ \Rightarrow\ 5x = 40 \]
\[ \frac{5x}{5} = \frac{40}{5} \ \Rightarrow\ x = 8 \]
\[ 5\cdot8 - 12 = 40 - 12 = 28 \checkmark \]

Trying values of x in 5x āˆ’ 12 = 28

x5x āˆ’ 12Equals 28?
618no
723no
828yes
933no
1038no

Questions

What is x in 5x āˆ’ 12 = 28?

The solution of 5x āˆ’ 12 = 28 is x = 8.

How do you solve 5x āˆ’ 12 = 28?

Add 12 to both sides to get 5x = 40, then divide both sides by 5 to get x = 8.

How do I check the answer?

Replace x by 8: 5(8) āˆ’ 12 = 28, which is 28.

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