Solve 4x + 8 = ā12
The solution of 4x + 8 = ā12 is x = -5.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 8 from both sides:
- 3
Divide both sides by 4:
- 4
Check: put x = -5 back into the equation.
LaTeX source of the formulas on this page
\[ 4x + 8 = -12\ \Rightarrow\ x = -5 \]
\[ 4x + 8 = -12 \]
\[ 4x + 8 - 8 = -12 - 8 \ \Rightarrow\ 4x = -20 \]
\[ \frac{4x}{4} = \frac{-20}{4} \ \Rightarrow\ x = -5 \]
\[ 4\cdot(-5) + 8 = -20 + 8 = -12 \checkmark \]Trying values of x in 4x + 8 = ā12
| x | 4x + 8 | Equals -12? |
|---|---|---|
| -7 | -20 | no |
| -6 | -16 | no |
| -5 | -12 | yes |
| -4 | -8 | no |
| -3 | -4 | no |
Questions
What is x in 4x + 8 = ā12?
The solution of 4x + 8 = ā12 is x = -5.
How do you solve 4x + 8 = ā12?
Subtract 8 from both sides to get 4x = -20, then divide both sides by 4 to get x = -5.
How do I check the answer?
Replace x by -5: 4(-5) + 8 = -12, which is -12.