Solve 4x + 7 = 79
The solution of 4x + 7 = 79 is x = 18.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 7 from both sides:
- 3
Divide both sides by 4:
- 4
Check: put x = 18 back into the equation.
LaTeX source of the formulas on this page
\[ 4x + 7 = 79\ \Rightarrow\ x = 18 \]
\[ 4x + 7 = 79 \]
\[ 4x + 7 - 7 = 79 - 7 \ \Rightarrow\ 4x = 72 \]
\[ \frac{4x}{4} = \frac{72}{4} \ \Rightarrow\ x = 18 \]
\[ 4\cdot18 + 7 = 72 + 7 = 79 \checkmark \]Trying values of x in 4x + 7 = 79
| x | 4x + 7 | Equals 79? |
|---|---|---|
| 16 | 71 | no |
| 17 | 75 | no |
| 18 | 79 | yes |
| 19 | 83 | no |
| 20 | 87 | no |
Questions
What is x in 4x + 7 = 79?
The solution of 4x + 7 = 79 is x = 18.
How do you solve 4x + 7 = 79?
Subtract 7 from both sides to get 4x = 72, then divide both sides by 4 to get x = 18.
How do I check the answer?
Replace x by 18: 4(18) + 7 = 79, which is 79.