Solve 4x + 7 = 63
The solution of 4x + 7 = 63 is x = 14.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 7 from both sides:
- 3
Divide both sides by 4:
- 4
Check: put x = 14 back into the equation.
LaTeX source of the formulas on this page
\[ 4x + 7 = 63\ \Rightarrow\ x = 14 \]
\[ 4x + 7 = 63 \]
\[ 4x + 7 - 7 = 63 - 7 \ \Rightarrow\ 4x = 56 \]
\[ \frac{4x}{4} = \frac{56}{4} \ \Rightarrow\ x = 14 \]
\[ 4\cdot14 + 7 = 56 + 7 = 63 \checkmark \]Trying values of x in 4x + 7 = 63
| x | 4x + 7 | Equals 63? |
|---|---|---|
| 12 | 55 | no |
| 13 | 59 | no |
| 14 | 63 | yes |
| 15 | 67 | no |
| 16 | 71 | no |
Questions
What is x in 4x + 7 = 63?
The solution of 4x + 7 = 63 is x = 14.
How do you solve 4x + 7 = 63?
Subtract 7 from both sides to get 4x = 56, then divide both sides by 4 to get x = 14.
How do I check the answer?
Replace x by 14: 4(14) + 7 = 63, which is 63.