Solve 4x + 5 = 41
The solution of 4x + 5 = 41 is x = 9.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 5 from both sides:
- 3
Divide both sides by 4:
- 4
Check: put x = 9 back into the equation.
LaTeX source of the formulas on this page
\[ 4x + 5 = 41\ \Rightarrow\ x = 9 \]
\[ 4x + 5 = 41 \]
\[ 4x + 5 - 5 = 41 - 5 \ \Rightarrow\ 4x = 36 \]
\[ \frac{4x}{4} = \frac{36}{4} \ \Rightarrow\ x = 9 \]
\[ 4\cdot9 + 5 = 36 + 5 = 41 \checkmark \]Trying values of x in 4x + 5 = 41
| x | 4x + 5 | Equals 41? |
|---|---|---|
| 7 | 33 | no |
| 8 | 37 | no |
| 9 | 41 | yes |
| 10 | 45 | no |
| 11 | 49 | no |
Questions
What is x in 4x + 5 = 41?
The solution of 4x + 5 = 41 is x = 9.
How do you solve 4x + 5 = 41?
Subtract 5 from both sides to get 4x = 36, then divide both sides by 4 to get x = 9.
How do I check the answer?
Replace x by 9: 4(9) + 5 = 41, which is 41.