Solve 4x + 4 = 80
The solution of 4x + 4 = 80 is x = 19.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 4 from both sides:
- 3
Divide both sides by 4:
- 4
Check: put x = 19 back into the equation.
LaTeX source of the formulas on this page
\[ 4x + 4 = 80\ \Rightarrow\ x = 19 \]
\[ 4x + 4 = 80 \]
\[ 4x + 4 - 4 = 80 - 4 \ \Rightarrow\ 4x = 76 \]
\[ \frac{4x}{4} = \frac{76}{4} \ \Rightarrow\ x = 19 \]
\[ 4\cdot19 + 4 = 76 + 4 = 80 \checkmark \]Trying values of x in 4x + 4 = 80
| x | 4x + 4 | Equals 80? |
|---|---|---|
| 17 | 72 | no |
| 18 | 76 | no |
| 19 | 80 | yes |
| 20 | 84 | no |
| 21 | 88 | no |
Questions
What is x in 4x + 4 = 80?
The solution of 4x + 4 = 80 is x = 19.
How do you solve 4x + 4 = 80?
Subtract 4 from both sides to get 4x = 76, then divide both sides by 4 to get x = 19.
How do I check the answer?
Replace x by 19: 4(19) + 4 = 80, which is 80.