Solve 4x + 4 = 4
The solution of 4x + 4 = 4 is x = 0.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 4 from both sides:
- 3
Divide both sides by 4:
- 4
Check: put x = 0 back into the equation.
LaTeX source of the formulas on this page
\[ 4x + 4 = 4\ \Rightarrow\ x = 0 \]
\[ 4x + 4 = 4 \]
\[ 4x + 4 - 4 = 4 - 4 \ \Rightarrow\ 4x = 0 \]
\[ \frac{4x}{4} = \frac{0}{4} \ \Rightarrow\ x = 0 \]
\[ 4\cdot0 + 4 = 0 + 4 = 4 \checkmark \]Trying values of x in 4x + 4 = 4
| x | 4x + 4 | Equals 4? |
|---|---|---|
| -2 | -4 | no |
| -1 | 0 | no |
| 0 | 4 | yes |
| 1 | 8 | no |
| 2 | 12 | no |
Questions
What is x in 4x + 4 = 4?
The solution of 4x + 4 = 4 is x = 0.
How do you solve 4x + 4 = 4?
Subtract 4 from both sides to get 4x = 0, then divide both sides by 4 to get x = 0.
How do I check the answer?
Replace x by 0: 4(0) + 4 = 4, which is 4.