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Solve 4x + 2 = āˆ’38

The solution of 4x + 2 = āˆ’38 is x = -10.

The lines y = 4x + 2 and y = -38 meet at x = -10-16-14-12-10-8-6-4-60-50-40-30-20-10x = -10y = 4x + 2y = -38
The lines y = 4x + 2 and y = -38 meet at x = -10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    4x+2=āˆ’384x + 2 = -38
  2. 2

    Subtract 2 from both sides:

    4x+2āˆ’2=āˆ’38āˆ’2 ⇒ 4x=āˆ’404x + 2 - 2 = -38 - 2 \ \Rightarrow\ 4x = -40
  3. 3

    Divide both sides by 4:

    4x4=āˆ’404 ⇒ x=āˆ’10\frac{4x}{4} = \frac{-40}{4} \ \Rightarrow\ x = -10
  4. 4

    Check: put x = -10 back into the equation.

    4ā‹…(āˆ’10)+2=āˆ’40+2=āˆ’38āœ“4\cdot(-10) + 2 = -40 + 2 = -38 \checkmark
LaTeX source of the formulas on this page
\[ 4x + 2 = -38\ \Rightarrow\ x = -10 \]
\[ 4x + 2 = -38 \]
\[ 4x + 2 - 2 = -38 - 2 \ \Rightarrow\ 4x = -40 \]
\[ \frac{4x}{4} = \frac{-40}{4} \ \Rightarrow\ x = -10 \]
\[ 4\cdot(-10) + 2 = -40 + 2 = -38 \checkmark \]

Trying values of x in 4x + 2 = āˆ’38

x4x + 2Equals -38?
-12-46no
-11-42no
-10-38yes
-9-34no
-8-30no

Questions

What is x in 4x + 2 = āˆ’38?

The solution of 4x + 2 = āˆ’38 is x = -10.

How do you solve 4x + 2 = āˆ’38?

Subtract 2 from both sides to get 4x = -40, then divide both sides by 4 to get x = -10.

How do I check the answer?

Replace x by -10: 4(-10) + 2 = -38, which is -38.

Similar equations

    Solve 4x + 2 = āˆ’38: x = -10 (steps and check) | WordGPT