Solve 4x + 12 = 64

The solution of 4x + 12 = 64 is x = 13.

4x + 12 = 64\ \Rightarrow\ x = 13

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The lines y = 4x + 12 and y = 64 meet at x = 13. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
$4x + 12 = 64$
2
Subtract 12 from both sides:
$4x + 12 - 12 = 64 - 12 \ \Rightarrow\ 4x = 52$
3
Divide both sides by 4:
$\frac{4x}{4} = \frac{52}{4} \ \Rightarrow\ x = 13$
4
Check: put x = 13 back into the equation.
$4\cdot13 + 12 = 52 + 12 = 64 \checkmark$

LaTeX source of the formulas on this page

\[ 4x + 12 = 64\ \Rightarrow\ x = 13 \]
\[ 4x + 12 = 64 \]
\[ 4x + 12 - 12 = 64 - 12 \ \Rightarrow\ 4x = 52 \]
\[ \frac{4x}{4} = \frac{52}{4} \ \Rightarrow\ x = 13 \]
\[ 4\cdot13 + 12 = 52 + 12 = 64 \checkmark \]

Trying values of x in 4x + 12 = 64

x	4x + 12	Equals 64?
11	56	no
12	60	no
13	64	yes
14	68	no
15	72	no

Questions

What is x in 4x + 12 = 64?

The solution of 4x + 12 = 64 is x = 13.

How do you solve 4x + 12 = 64?

Subtract 12 from both sides to get 4x = 52, then divide both sides by 4 to get x = 13.

How do I check the answer?

Replace x by 13: 4(13) + 12 = 64, which is 64.

Solve 4x + 12 = 64

How to work it out

Trying values of x in 4x + 12 = 64

Questions

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