Solve 4x + 12 = 40
The solution of 4x + 12 = 40 is x = 7.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 12 from both sides:
- 3
Divide both sides by 4:
- 4
Check: put x = 7 back into the equation.
LaTeX source of the formulas on this page
\[ 4x + 12 = 40\ \Rightarrow\ x = 7 \]
\[ 4x + 12 = 40 \]
\[ 4x + 12 - 12 = 40 - 12 \ \Rightarrow\ 4x = 28 \]
\[ \frac{4x}{4} = \frac{28}{4} \ \Rightarrow\ x = 7 \]
\[ 4\cdot7 + 12 = 28 + 12 = 40 \checkmark \]Trying values of x in 4x + 12 = 40
| x | 4x + 12 | Equals 40? |
|---|---|---|
| 5 | 32 | no |
| 6 | 36 | no |
| 7 | 40 | yes |
| 8 | 44 | no |
| 9 | 48 | no |
Questions
What is x in 4x + 12 = 40?
The solution of 4x + 12 = 40 is x = 7.
How do you solve 4x + 12 = 40?
Subtract 12 from both sides to get 4x = 28, then divide both sides by 4 to get x = 7.
How do I check the answer?
Replace x by 7: 4(7) + 12 = 40, which is 40.