Solve 4x + 12 = 16

The solution of 4x + 12 = 16 is x = 1.

4x + 12 = 16\ \Rightarrow\ x = 1

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The lines y = 4x + 12 and y = 16 meet at x = 1. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
$4x + 12 = 16$
2
Subtract 12 from both sides:
$4x + 12 - 12 = 16 - 12 \ \Rightarrow\ 4x = 4$
3
Divide both sides by 4:
$\frac{4x}{4} = \frac{4}{4} \ \Rightarrow\ x = 1$
4
Check: put x = 1 back into the equation.
$4\cdot1 + 12 = 4 + 12 = 16 \checkmark$

LaTeX source of the formulas on this page

\[ 4x + 12 = 16\ \Rightarrow\ x = 1 \]
\[ 4x + 12 = 16 \]
\[ 4x + 12 - 12 = 16 - 12 \ \Rightarrow\ 4x = 4 \]
\[ \frac{4x}{4} = \frac{4}{4} \ \Rightarrow\ x = 1 \]
\[ 4\cdot1 + 12 = 4 + 12 = 16 \checkmark \]

Trying values of x in 4x + 12 = 16

x	4x + 12	Equals 16?
-1	8	no
0	12	no
1	16	yes
2	20	no
3	24	no

Questions

What is x in 4x + 12 = 16?

The solution of 4x + 12 = 16 is x = 1.

How do you solve 4x + 12 = 16?

Subtract 12 from both sides to get 4x = 4, then divide both sides by 4 to get x = 1.

How do I check the answer?

Replace x by 1: 4(1) + 12 = 16, which is 16.

Solve 4x + 12 = 16

How to work it out

Trying values of x in 4x + 12 = 16

Questions

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