Solve 4x + 1 = 81
The solution of 4x + 1 = 81 is x = 20.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 4:
- 4
Check: put x = 20 back into the equation.
LaTeX source of the formulas on this page
\[ 4x + 1 = 81\ \Rightarrow\ x = 20 \]
\[ 4x + 1 = 81 \]
\[ 4x + 1 - 1 = 81 - 1 \ \Rightarrow\ 4x = 80 \]
\[ \frac{4x}{4} = \frac{80}{4} \ \Rightarrow\ x = 20 \]
\[ 4\cdot20 + 1 = 80 + 1 = 81 \checkmark \]Trying values of x in 4x + 1 = 81
| x | 4x + 1 | Equals 81? |
|---|---|---|
| 18 | 73 | no |
| 19 | 77 | no |
| 20 | 81 | yes |
| 21 | 85 | no |
| 22 | 89 | no |
Questions
What is x in 4x + 1 = 81?
The solution of 4x + 1 = 81 is x = 20.
How do you solve 4x + 1 = 81?
Subtract 1 from both sides to get 4x = 80, then divide both sides by 4 to get x = 20.
How do I check the answer?
Replace x by 20: 4(20) + 1 = 81, which is 81.