Solve 4x ā 9 = 63
The solution of 4x ā 9 = 63 is x = 18.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 9 to both sides:
- 3
Divide both sides by 4:
- 4
Check: put x = 18 back into the equation.
LaTeX source of the formulas on this page
\[ 4x - 9 = 63\ \Rightarrow\ x = 18 \]
\[ 4x - 9 = 63 \]
\[ 4x - 9 + 9 = 63 + 9 \ \Rightarrow\ 4x = 72 \]
\[ \frac{4x}{4} = \frac{72}{4} \ \Rightarrow\ x = 18 \]
\[ 4\cdot18 - 9 = 72 - 9 = 63 \checkmark \]Trying values of x in 4x ā 9 = 63
| x | 4x ā 9 | Equals 63? |
|---|---|---|
| 16 | 55 | no |
| 17 | 59 | no |
| 18 | 63 | yes |
| 19 | 67 | no |
| 20 | 71 | no |
Questions
What is x in 4x ā 9 = 63?
The solution of 4x ā 9 = 63 is x = 18.
How do you solve 4x ā 9 = 63?
Add 9 to both sides to get 4x = 72, then divide both sides by 4 to get x = 18.
How do I check the answer?
Replace x by 18: 4(18) ā 9 = 63, which is 63.