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Solve 4x āˆ’ 8 = 32

The solution of 4x āˆ’ 8 = 32 is x = 10.

The lines y = 4x āˆ’ 8 and y = 32 meet at x = 1046810121416102030405060x = 10y = 4x āˆ’ 8y = 32
The lines y = 4x āˆ’ 8 and y = 32 meet at x = 10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    4xāˆ’8=324x - 8 = 32
  2. 2

    Add 8 to both sides:

    4xāˆ’8+8=32+8 ⇒ 4x=404x - 8 + 8 = 32 + 8 \ \Rightarrow\ 4x = 40
  3. 3

    Divide both sides by 4:

    4x4=404 ⇒ x=10\frac{4x}{4} = \frac{40}{4} \ \Rightarrow\ x = 10
  4. 4

    Check: put x = 10 back into the equation.

    4ā‹…10āˆ’8=40āˆ’8=32āœ“4\cdot10 - 8 = 40 - 8 = 32 \checkmark
LaTeX source of the formulas on this page
\[ 4x - 8 = 32\ \Rightarrow\ x = 10 \]
\[ 4x - 8 = 32 \]
\[ 4x - 8 + 8 = 32 + 8 \ \Rightarrow\ 4x = 40 \]
\[ \frac{4x}{4} = \frac{40}{4} \ \Rightarrow\ x = 10 \]
\[ 4\cdot10 - 8 = 40 - 8 = 32 \checkmark \]

Trying values of x in 4x āˆ’ 8 = 32

x4x āˆ’ 8Equals 32?
824no
928no
1032yes
1136no
1240no

Questions

What is x in 4x āˆ’ 8 = 32?

The solution of 4x āˆ’ 8 = 32 is x = 10.

How do you solve 4x āˆ’ 8 = 32?

Add 8 to both sides to get 4x = 40, then divide both sides by 4 to get x = 10.

How do I check the answer?

Replace x by 10: 4(10) āˆ’ 8 = 32, which is 32.

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