Solve 4x ā 5 = ā45
The solution of 4x ā 5 = ā45 is x = -10.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 5 to both sides:
- 3
Divide both sides by 4:
- 4
Check: put x = -10 back into the equation.
LaTeX source of the formulas on this page
\[ 4x - 5 = -45\ \Rightarrow\ x = -10 \]
\[ 4x - 5 = -45 \]
\[ 4x - 5 + 5 = -45 + 5 \ \Rightarrow\ 4x = -40 \]
\[ \frac{4x}{4} = \frac{-40}{4} \ \Rightarrow\ x = -10 \]
\[ 4\cdot(-10) - 5 = -40 - 5 = -45 \checkmark \]Trying values of x in 4x ā 5 = ā45
| x | 4x ā 5 | Equals -45? |
|---|---|---|
| -12 | -53 | no |
| -11 | -49 | no |
| -10 | -45 | yes |
| -9 | -41 | no |
| -8 | -37 | no |
Questions
What is x in 4x ā 5 = ā45?
The solution of 4x ā 5 = ā45 is x = -10.
How do you solve 4x ā 5 = ā45?
Add 5 to both sides to get 4x = -40, then divide both sides by 4 to get x = -10.
How do I check the answer?
Replace x by -10: 4(-10) ā 5 = -45, which is -45.