Solve 4x ā 5 = 63
The solution of 4x ā 5 = 63 is x = 17.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 5 to both sides:
- 3
Divide both sides by 4:
- 4
Check: put x = 17 back into the equation.
LaTeX source of the formulas on this page
\[ 4x - 5 = 63\ \Rightarrow\ x = 17 \]
\[ 4x - 5 = 63 \]
\[ 4x - 5 + 5 = 63 + 5 \ \Rightarrow\ 4x = 68 \]
\[ \frac{4x}{4} = \frac{68}{4} \ \Rightarrow\ x = 17 \]
\[ 4\cdot17 - 5 = 68 - 5 = 63 \checkmark \]Trying values of x in 4x ā 5 = 63
| x | 4x ā 5 | Equals 63? |
|---|---|---|
| 15 | 55 | no |
| 16 | 59 | no |
| 17 | 63 | yes |
| 18 | 67 | no |
| 19 | 71 | no |
Questions
What is x in 4x ā 5 = 63?
The solution of 4x ā 5 = 63 is x = 17.
How do you solve 4x ā 5 = 63?
Add 5 to both sides to get 4x = 68, then divide both sides by 4 to get x = 17.
How do I check the answer?
Replace x by 17: 4(17) ā 5 = 63, which is 63.