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Solve 4x āˆ’ 5 = 43

The solution of 4x āˆ’ 5 = 43 is x = 12.

The lines y = 4x āˆ’ 5 and y = 43 meet at x = 12681012141618203040506070x = 12y = 4x āˆ’ 5y = 43
The lines y = 4x āˆ’ 5 and y = 43 meet at x = 12. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    4xāˆ’5=434x - 5 = 43
  2. 2

    Add 5 to both sides:

    4xāˆ’5+5=43+5 ⇒ 4x=484x - 5 + 5 = 43 + 5 \ \Rightarrow\ 4x = 48
  3. 3

    Divide both sides by 4:

    4x4=484 ⇒ x=12\frac{4x}{4} = \frac{48}{4} \ \Rightarrow\ x = 12
  4. 4

    Check: put x = 12 back into the equation.

    4ā‹…12āˆ’5=48āˆ’5=43āœ“4\cdot12 - 5 = 48 - 5 = 43 \checkmark
LaTeX source of the formulas on this page
\[ 4x - 5 = 43\ \Rightarrow\ x = 12 \]
\[ 4x - 5 = 43 \]
\[ 4x - 5 + 5 = 43 + 5 \ \Rightarrow\ 4x = 48 \]
\[ \frac{4x}{4} = \frac{48}{4} \ \Rightarrow\ x = 12 \]
\[ 4\cdot12 - 5 = 48 - 5 = 43 \checkmark \]

Trying values of x in 4x āˆ’ 5 = 43

x4x āˆ’ 5Equals 43?
1035no
1139no
1243yes
1347no
1451no

Questions

What is x in 4x āˆ’ 5 = 43?

The solution of 4x āˆ’ 5 = 43 is x = 12.

How do you solve 4x āˆ’ 5 = 43?

Add 5 to both sides to get 4x = 48, then divide both sides by 4 to get x = 12.

How do I check the answer?

Replace x by 12: 4(12) āˆ’ 5 = 43, which is 43.

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    Solve 4x āˆ’ 5 = 43: x = 12 (steps and check) | WordGPT