Solve 4x ā 2 = 38
The solution of 4x ā 2 = 38 is x = 10.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 2 to both sides:
- 3
Divide both sides by 4:
- 4
Check: put x = 10 back into the equation.
LaTeX source of the formulas on this page
\[ 4x - 2 = 38\ \Rightarrow\ x = 10 \]
\[ 4x - 2 = 38 \]
\[ 4x - 2 + 2 = 38 + 2 \ \Rightarrow\ 4x = 40 \]
\[ \frac{4x}{4} = \frac{40}{4} \ \Rightarrow\ x = 10 \]
\[ 4\cdot10 - 2 = 40 - 2 = 38 \checkmark \]Trying values of x in 4x ā 2 = 38
| x | 4x ā 2 | Equals 38? |
|---|---|---|
| 8 | 30 | no |
| 9 | 34 | no |
| 10 | 38 | yes |
| 11 | 42 | no |
| 12 | 46 | no |
Questions
What is x in 4x ā 2 = 38?
The solution of 4x ā 2 = 38 is x = 10.
How do you solve 4x ā 2 = 38?
Add 2 to both sides to get 4x = 40, then divide both sides by 4 to get x = 10.
How do I check the answer?
Replace x by 10: 4(10) ā 2 = 38, which is 38.