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Solve 4x āˆ’ 15 = āˆ’15

The solution of 4x āˆ’ 15 = āˆ’15 is x = 0.

The lines y = 4x āˆ’ 15 and y = -15 meet at x = 0-6-4-2246-40-30-20-1010x = 0y = 4x āˆ’ 15y = -15
The lines y = 4x āˆ’ 15 and y = -15 meet at x = 0. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    4xāˆ’15=āˆ’154x - 15 = -15
  2. 2

    Add 15 to both sides:

    4xāˆ’15+15=āˆ’15+15 ⇒ 4x=04x - 15 + 15 = -15 + 15 \ \Rightarrow\ 4x = 0
  3. 3

    Divide both sides by 4:

    4x4=04 ⇒ x=0\frac{4x}{4} = \frac{0}{4} \ \Rightarrow\ x = 0
  4. 4

    Check: put x = 0 back into the equation.

    4ā‹…0āˆ’15=0āˆ’15=āˆ’15āœ“4\cdot0 - 15 = 0 - 15 = -15 \checkmark
LaTeX source of the formulas on this page
\[ 4x - 15 = -15\ \Rightarrow\ x = 0 \]
\[ 4x - 15 = -15 \]
\[ 4x - 15 + 15 = -15 + 15 \ \Rightarrow\ 4x = 0 \]
\[ \frac{4x}{4} = \frac{0}{4} \ \Rightarrow\ x = 0 \]
\[ 4\cdot0 - 15 = 0 - 15 = -15 \checkmark \]

Trying values of x in 4x āˆ’ 15 = āˆ’15

x4x āˆ’ 15Equals -15?
-2-23no
-1-19no
0-15yes
1-11no
2-7no

Questions

What is x in 4x āˆ’ 15 = āˆ’15?

The solution of 4x āˆ’ 15 = āˆ’15 is x = 0.

How do you solve 4x āˆ’ 15 = āˆ’15?

Add 15 to both sides to get 4x = 0, then divide both sides by 4 to get x = 0.

How do I check the answer?

Replace x by 0: 4(0) āˆ’ 15 = -15, which is -15.

Similar equations

    Solve 4x āˆ’ 15 = āˆ’15: x = 0 (steps and check) | WordGPT