Solve 4x ā 15 = 29
The solution of 4x ā 15 = 29 is x = 11.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 15 to both sides:
- 3
Divide both sides by 4:
- 4
Check: put x = 11 back into the equation.
LaTeX source of the formulas on this page
\[ 4x - 15 = 29\ \Rightarrow\ x = 11 \]
\[ 4x - 15 = 29 \]
\[ 4x - 15 + 15 = 29 + 15 \ \Rightarrow\ 4x = 44 \]
\[ \frac{4x}{4} = \frac{44}{4} \ \Rightarrow\ x = 11 \]
\[ 4\cdot11 - 15 = 44 - 15 = 29 \checkmark \]Trying values of x in 4x ā 15 = 29
| x | 4x ā 15 | Equals 29? |
|---|---|---|
| 9 | 21 | no |
| 10 | 25 | no |
| 11 | 29 | yes |
| 12 | 33 | no |
| 13 | 37 | no |
Questions
What is x in 4x ā 15 = 29?
The solution of 4x ā 15 = 29 is x = 11.
How do you solve 4x ā 15 = 29?
Add 15 to both sides to get 4x = 44, then divide both sides by 4 to get x = 11.
How do I check the answer?
Replace x by 11: 4(11) ā 15 = 29, which is 29.