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Solve 4x āˆ’ 12 = 4

The solution of 4x āˆ’ 12 = 4 is x = 4.

The lines y = 4x āˆ’ 12 and y = 4 meet at x = 4-2246810-20-10102030x = 4y = 4x āˆ’ 12y = 4
The lines y = 4x āˆ’ 12 and y = 4 meet at x = 4. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    4xāˆ’12=44x - 12 = 4
  2. 2

    Add 12 to both sides:

    4xāˆ’12+12=4+12 ⇒ 4x=164x - 12 + 12 = 4 + 12 \ \Rightarrow\ 4x = 16
  3. 3

    Divide both sides by 4:

    4x4=164 ⇒ x=4\frac{4x}{4} = \frac{16}{4} \ \Rightarrow\ x = 4
  4. 4

    Check: put x = 4 back into the equation.

    4ā‹…4āˆ’12=16āˆ’12=4āœ“4\cdot4 - 12 = 16 - 12 = 4 \checkmark
LaTeX source of the formulas on this page
\[ 4x - 12 = 4\ \Rightarrow\ x = 4 \]
\[ 4x - 12 = 4 \]
\[ 4x - 12 + 12 = 4 + 12 \ \Rightarrow\ 4x = 16 \]
\[ \frac{4x}{4} = \frac{16}{4} \ \Rightarrow\ x = 4 \]
\[ 4\cdot4 - 12 = 16 - 12 = 4 \checkmark \]

Trying values of x in 4x āˆ’ 12 = 4

x4x āˆ’ 12Equals 4?
2-4no
30no
44yes
58no
612no

Questions

What is x in 4x āˆ’ 12 = 4?

The solution of 4x āˆ’ 12 = 4 is x = 4.

How do you solve 4x āˆ’ 12 = 4?

Add 12 to both sides to get 4x = 16, then divide both sides by 4 to get x = 4.

How do I check the answer?

Replace x by 4: 4(4) āˆ’ 12 = 4, which is 4.

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