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Solve 4x āˆ’ 12 = 28

The solution of 4x āˆ’ 12 = 28 is x = 10.

The lines y = 4x āˆ’ 12 and y = 28 meet at x = 10468101214161020304050x = 10y = 4x āˆ’ 12y = 28
The lines y = 4x āˆ’ 12 and y = 28 meet at x = 10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    4xāˆ’12=284x - 12 = 28
  2. 2

    Add 12 to both sides:

    4xāˆ’12+12=28+12 ⇒ 4x=404x - 12 + 12 = 28 + 12 \ \Rightarrow\ 4x = 40
  3. 3

    Divide both sides by 4:

    4x4=404 ⇒ x=10\frac{4x}{4} = \frac{40}{4} \ \Rightarrow\ x = 10
  4. 4

    Check: put x = 10 back into the equation.

    4ā‹…10āˆ’12=40āˆ’12=28āœ“4\cdot10 - 12 = 40 - 12 = 28 \checkmark
LaTeX source of the formulas on this page
\[ 4x - 12 = 28\ \Rightarrow\ x = 10 \]
\[ 4x - 12 = 28 \]
\[ 4x - 12 + 12 = 28 + 12 \ \Rightarrow\ 4x = 40 \]
\[ \frac{4x}{4} = \frac{40}{4} \ \Rightarrow\ x = 10 \]
\[ 4\cdot10 - 12 = 40 - 12 = 28 \checkmark \]

Trying values of x in 4x āˆ’ 12 = 28

x4x āˆ’ 12Equals 28?
820no
924no
1028yes
1132no
1236no

Questions

What is x in 4x āˆ’ 12 = 28?

The solution of 4x āˆ’ 12 = 28 is x = 10.

How do you solve 4x āˆ’ 12 = 28?

Add 12 to both sides to get 4x = 40, then divide both sides by 4 to get x = 10.

How do I check the answer?

Replace x by 10: 4(10) āˆ’ 12 = 28, which is 28.

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