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Solve 4x āˆ’ 11 = 29

The solution of 4x āˆ’ 11 = 29 is x = 10.

The lines y = 4x āˆ’ 11 and y = 29 meet at x = 10468101214161020304050x = 10y = 4x āˆ’ 11y = 29
The lines y = 4x āˆ’ 11 and y = 29 meet at x = 10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    4xāˆ’11=294x - 11 = 29
  2. 2

    Add 11 to both sides:

    4xāˆ’11+11=29+11 ⇒ 4x=404x - 11 + 11 = 29 + 11 \ \Rightarrow\ 4x = 40
  3. 3

    Divide both sides by 4:

    4x4=404 ⇒ x=10\frac{4x}{4} = \frac{40}{4} \ \Rightarrow\ x = 10
  4. 4

    Check: put x = 10 back into the equation.

    4ā‹…10āˆ’11=40āˆ’11=29āœ“4\cdot10 - 11 = 40 - 11 = 29 \checkmark
LaTeX source of the formulas on this page
\[ 4x - 11 = 29\ \Rightarrow\ x = 10 \]
\[ 4x - 11 = 29 \]
\[ 4x - 11 + 11 = 29 + 11 \ \Rightarrow\ 4x = 40 \]
\[ \frac{4x}{4} = \frac{40}{4} \ \Rightarrow\ x = 10 \]
\[ 4\cdot10 - 11 = 40 - 11 = 29 \checkmark \]

Trying values of x in 4x āˆ’ 11 = 29

x4x āˆ’ 11Equals 29?
821no
925no
1029yes
1133no
1237no

Questions

What is x in 4x āˆ’ 11 = 29?

The solution of 4x āˆ’ 11 = 29 is x = 10.

How do you solve 4x āˆ’ 11 = 29?

Add 11 to both sides to get 4x = 40, then divide both sides by 4 to get x = 10.

How do I check the answer?

Replace x by 10: 4(10) āˆ’ 11 = 29, which is 29.

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