Solve 3x + 7 = 40
The solution of 3x + 7 = 40 is x = 11.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 7 from both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = 11 back into the equation.
LaTeX source of the formulas on this page
\[ 3x + 7 = 40\ \Rightarrow\ x = 11 \]
\[ 3x + 7 = 40 \]
\[ 3x + 7 - 7 = 40 - 7 \ \Rightarrow\ 3x = 33 \]
\[ \frac{3x}{3} = \frac{33}{3} \ \Rightarrow\ x = 11 \]
\[ 3\cdot11 + 7 = 33 + 7 = 40 \checkmark \]Trying values of x in 3x + 7 = 40
| x | 3x + 7 | Equals 40? |
|---|---|---|
| 9 | 34 | no |
| 10 | 37 | no |
| 11 | 40 | yes |
| 12 | 43 | no |
| 13 | 46 | no |
Questions
What is x in 3x + 7 = 40?
The solution of 3x + 7 = 40 is x = 11.
How do you solve 3x + 7 = 40?
Subtract 7 from both sides to get 3x = 33, then divide both sides by 3 to get x = 11.
How do I check the answer?
Replace x by 11: 3(11) + 7 = 40, which is 40.