Solve 3x + 6 = ā12
The solution of 3x + 6 = ā12 is x = -6.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 6 from both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = -6 back into the equation.
LaTeX source of the formulas on this page
\[ 3x + 6 = -12\ \Rightarrow\ x = -6 \]
\[ 3x + 6 = -12 \]
\[ 3x + 6 - 6 = -12 - 6 \ \Rightarrow\ 3x = -18 \]
\[ \frac{3x}{3} = \frac{-18}{3} \ \Rightarrow\ x = -6 \]
\[ 3\cdot(-6) + 6 = -18 + 6 = -12 \checkmark \]Trying values of x in 3x + 6 = ā12
| x | 3x + 6 | Equals -12? |
|---|---|---|
| -8 | -18 | no |
| -7 | -15 | no |
| -6 | -12 | yes |
| -5 | -9 | no |
| -4 | -6 | no |
Questions
What is x in 3x + 6 = ā12?
The solution of 3x + 6 = ā12 is x = -6.
How do you solve 3x + 6 = ā12?
Subtract 6 from both sides to get 3x = -18, then divide both sides by 3 to get x = -6.
How do I check the answer?
Replace x by -6: 3(-6) + 6 = -12, which is -12.