Solve 3x + 6 = 63
The solution of 3x + 6 = 63 is x = 19.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 6 from both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = 19 back into the equation.
LaTeX source of the formulas on this page
\[ 3x + 6 = 63\ \Rightarrow\ x = 19 \]
\[ 3x + 6 = 63 \]
\[ 3x + 6 - 6 = 63 - 6 \ \Rightarrow\ 3x = 57 \]
\[ \frac{3x}{3} = \frac{57}{3} \ \Rightarrow\ x = 19 \]
\[ 3\cdot19 + 6 = 57 + 6 = 63 \checkmark \]Trying values of x in 3x + 6 = 63
| x | 3x + 6 | Equals 63? |
|---|---|---|
| 17 | 57 | no |
| 18 | 60 | no |
| 19 | 63 | yes |
| 20 | 66 | no |
| 21 | 69 | no |
Questions
What is x in 3x + 6 = 63?
The solution of 3x + 6 = 63 is x = 19.
How do you solve 3x + 6 = 63?
Subtract 6 from both sides to get 3x = 57, then divide both sides by 3 to get x = 19.
How do I check the answer?
Replace x by 19: 3(19) + 6 = 63, which is 63.