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Solve 3x + 5 = āˆ’10

The solution of 3x + 5 = āˆ’10 is x = -5.

The lines y = 3x + 5 and y = -10 meet at x = -5-10-8-6-4-2-30-25-20-15-10-5510x = -5y = 3x + 5y = -10
The lines y = 3x + 5 and y = -10 meet at x = -5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    3x+5=āˆ’103x + 5 = -10
  2. 2

    Subtract 5 from both sides:

    3x+5āˆ’5=āˆ’10āˆ’5 ⇒ 3x=āˆ’153x + 5 - 5 = -10 - 5 \ \Rightarrow\ 3x = -15
  3. 3

    Divide both sides by 3:

    3x3=āˆ’153 ⇒ x=āˆ’5\frac{3x}{3} = \frac{-15}{3} \ \Rightarrow\ x = -5
  4. 4

    Check: put x = -5 back into the equation.

    3ā‹…(āˆ’5)+5=āˆ’15+5=āˆ’10āœ“3\cdot(-5) + 5 = -15 + 5 = -10 \checkmark
LaTeX source of the formulas on this page
\[ 3x + 5 = -10\ \Rightarrow\ x = -5 \]
\[ 3x + 5 = -10 \]
\[ 3x + 5 - 5 = -10 - 5 \ \Rightarrow\ 3x = -15 \]
\[ \frac{3x}{3} = \frac{-15}{3} \ \Rightarrow\ x = -5 \]
\[ 3\cdot(-5) + 5 = -15 + 5 = -10 \checkmark \]

Trying values of x in 3x + 5 = āˆ’10

x3x + 5Equals -10?
-7-16no
-6-13no
-5-10yes
-4-7no
-3-4no

Questions

What is x in 3x + 5 = āˆ’10?

The solution of 3x + 5 = āˆ’10 is x = -5.

How do you solve 3x + 5 = āˆ’10?

Subtract 5 from both sides to get 3x = -15, then divide both sides by 3 to get x = -5.

How do I check the answer?

Replace x by -5: 3(-5) + 5 = -10, which is -10.

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    Solve 3x + 5 = āˆ’10: x = -5 (steps and check) | WordGPT