Solve 3x + 5 = ā1
The solution of 3x + 5 = ā1 is x = -2.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 5 from both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = -2 back into the equation.
LaTeX source of the formulas on this page
\[ 3x + 5 = -1\ \Rightarrow\ x = -2 \]
\[ 3x + 5 = -1 \]
\[ 3x + 5 - 5 = -1 - 5 \ \Rightarrow\ 3x = -6 \]
\[ \frac{3x}{3} = \frac{-6}{3} \ \Rightarrow\ x = -2 \]
\[ 3\cdot(-2) + 5 = -6 + 5 = -1 \checkmark \]Trying values of x in 3x + 5 = ā1
| x | 3x + 5 | Equals -1? |
|---|---|---|
| -4 | -7 | no |
| -3 | -4 | no |
| -2 | -1 | yes |
| -1 | 2 | no |
| 0 | 5 | no |
Questions
What is x in 3x + 5 = ā1?
The solution of 3x + 5 = ā1 is x = -2.
How do you solve 3x + 5 = ā1?
Subtract 5 from both sides to get 3x = -6, then divide both sides by 3 to get x = -2.
How do I check the answer?
Replace x by -2: 3(-2) + 5 = -1, which is -1.