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Solve 3x + 4 = āˆ’2

The solution of 3x + 4 = āˆ’2 is x = -2.

The lines y = 3x + 4 and y = -2 meet at x = -2-8-6-4-224-20-15-10-551015x = -2y = 3x + 4y = -2
The lines y = 3x + 4 and y = -2 meet at x = -2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    3x+4=āˆ’23x + 4 = -2
  2. 2

    Subtract 4 from both sides:

    3x+4āˆ’4=āˆ’2āˆ’4 ⇒ 3x=āˆ’63x + 4 - 4 = -2 - 4 \ \Rightarrow\ 3x = -6
  3. 3

    Divide both sides by 3:

    3x3=āˆ’63 ⇒ x=āˆ’2\frac{3x}{3} = \frac{-6}{3} \ \Rightarrow\ x = -2
  4. 4

    Check: put x = -2 back into the equation.

    3ā‹…(āˆ’2)+4=āˆ’6+4=āˆ’2āœ“3\cdot(-2) + 4 = -6 + 4 = -2 \checkmark
LaTeX source of the formulas on this page
\[ 3x + 4 = -2\ \Rightarrow\ x = -2 \]
\[ 3x + 4 = -2 \]
\[ 3x + 4 - 4 = -2 - 4 \ \Rightarrow\ 3x = -6 \]
\[ \frac{3x}{3} = \frac{-6}{3} \ \Rightarrow\ x = -2 \]
\[ 3\cdot(-2) + 4 = -6 + 4 = -2 \checkmark \]

Trying values of x in 3x + 4 = āˆ’2

x3x + 4Equals -2?
-4-8no
-3-5no
-2-2yes
-11no
04no

Questions

What is x in 3x + 4 = āˆ’2?

The solution of 3x + 4 = āˆ’2 is x = -2.

How do you solve 3x + 4 = āˆ’2?

Subtract 4 from both sides to get 3x = -6, then divide both sides by 3 to get x = -2.

How do I check the answer?

Replace x by -2: 3(-2) + 4 = -2, which is -2.

Similar equations

    Solve 3x + 4 = āˆ’2: x = -2 (steps and check) | WordGPT