Solve 3x + 3 = ā18
The solution of 3x + 3 = ā18 is x = -7.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 3 from both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = -7 back into the equation.
LaTeX source of the formulas on this page
\[ 3x + 3 = -18\ \Rightarrow\ x = -7 \]
\[ 3x + 3 = -18 \]
\[ 3x + 3 - 3 = -18 - 3 \ \Rightarrow\ 3x = -21 \]
\[ \frac{3x}{3} = \frac{-21}{3} \ \Rightarrow\ x = -7 \]
\[ 3\cdot(-7) + 3 = -21 + 3 = -18 \checkmark \]Trying values of x in 3x + 3 = ā18
| x | 3x + 3 | Equals -18? |
|---|---|---|
| -9 | -24 | no |
| -8 | -21 | no |
| -7 | -18 | yes |
| -6 | -15 | no |
| -5 | -12 | no |
Questions
What is x in 3x + 3 = ā18?
The solution of 3x + 3 = ā18 is x = -7.
How do you solve 3x + 3 = ā18?
Subtract 3 from both sides to get 3x = -21, then divide both sides by 3 to get x = -7.
How do I check the answer?
Replace x by -7: 3(-7) + 3 = -18, which is -18.