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Solve 3x + 3 = āˆ’12

The solution of 3x + 3 = āˆ’12 is x = -5.

The lines y = 3x + 3 and y = -12 meet at x = -5-10-8-6-4-2-30-25-20-15-10-55x = -5y = 3x + 3y = -12
The lines y = 3x + 3 and y = -12 meet at x = -5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    3x+3=āˆ’123x + 3 = -12
  2. 2

    Subtract 3 from both sides:

    3x+3āˆ’3=āˆ’12āˆ’3 ⇒ 3x=āˆ’153x + 3 - 3 = -12 - 3 \ \Rightarrow\ 3x = -15
  3. 3

    Divide both sides by 3:

    3x3=āˆ’153 ⇒ x=āˆ’5\frac{3x}{3} = \frac{-15}{3} \ \Rightarrow\ x = -5
  4. 4

    Check: put x = -5 back into the equation.

    3ā‹…(āˆ’5)+3=āˆ’15+3=āˆ’12āœ“3\cdot(-5) + 3 = -15 + 3 = -12 \checkmark
LaTeX source of the formulas on this page
\[ 3x + 3 = -12\ \Rightarrow\ x = -5 \]
\[ 3x + 3 = -12 \]
\[ 3x + 3 - 3 = -12 - 3 \ \Rightarrow\ 3x = -15 \]
\[ \frac{3x}{3} = \frac{-15}{3} \ \Rightarrow\ x = -5 \]
\[ 3\cdot(-5) + 3 = -15 + 3 = -12 \checkmark \]

Trying values of x in 3x + 3 = āˆ’12

x3x + 3Equals -12?
-7-18no
-6-15no
-5-12yes
-4-9no
-3-6no

Questions

What is x in 3x + 3 = āˆ’12?

The solution of 3x + 3 = āˆ’12 is x = -5.

How do you solve 3x + 3 = āˆ’12?

Subtract 3 from both sides to get 3x = -15, then divide both sides by 3 to get x = -5.

How do I check the answer?

Replace x by -5: 3(-5) + 3 = -12, which is -12.

Similar equations

    Solve 3x + 3 = āˆ’12: x = -5 (steps and check) | WordGPT