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Solve 3x + 2 = āˆ’13

The solution of 3x + 2 = āˆ’13 is x = -5.

The lines y = 3x + 2 and y = -13 meet at x = -5-10-8-6-4-2-30-25-20-15-10-55x = -5y = 3x + 2y = -13
The lines y = 3x + 2 and y = -13 meet at x = -5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    3x+2=āˆ’133x + 2 = -13
  2. 2

    Subtract 2 from both sides:

    3x+2āˆ’2=āˆ’13āˆ’2 ⇒ 3x=āˆ’153x + 2 - 2 = -13 - 2 \ \Rightarrow\ 3x = -15
  3. 3

    Divide both sides by 3:

    3x3=āˆ’153 ⇒ x=āˆ’5\frac{3x}{3} = \frac{-15}{3} \ \Rightarrow\ x = -5
  4. 4

    Check: put x = -5 back into the equation.

    3ā‹…(āˆ’5)+2=āˆ’15+2=āˆ’13āœ“3\cdot(-5) + 2 = -15 + 2 = -13 \checkmark
LaTeX source of the formulas on this page
\[ 3x + 2 = -13\ \Rightarrow\ x = -5 \]
\[ 3x + 2 = -13 \]
\[ 3x + 2 - 2 = -13 - 2 \ \Rightarrow\ 3x = -15 \]
\[ \frac{3x}{3} = \frac{-15}{3} \ \Rightarrow\ x = -5 \]
\[ 3\cdot(-5) + 2 = -15 + 2 = -13 \checkmark \]

Trying values of x in 3x + 2 = āˆ’13

x3x + 2Equals -13?
-7-19no
-6-16no
-5-13yes
-4-10no
-3-7no

Questions

What is x in 3x + 2 = āˆ’13?

The solution of 3x + 2 = āˆ’13 is x = -5.

How do you solve 3x + 2 = āˆ’13?

Subtract 2 from both sides to get 3x = -15, then divide both sides by 3 to get x = -5.

How do I check the answer?

Replace x by -5: 3(-5) + 2 = -13, which is -13.

Similar equations

    Solve 3x + 2 = āˆ’13: x = -5 (steps and check) | WordGPT