Solve 3x + 2 = 17
The solution of 3x + 2 = 17 is x = 5.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 2 from both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = 5 back into the equation.
LaTeX source of the formulas on this page
\[ 3x + 2 = 17\ \Rightarrow\ x = 5 \]
\[ 3x + 2 = 17 \]
\[ 3x + 2 - 2 = 17 - 2 \ \Rightarrow\ 3x = 15 \]
\[ \frac{3x}{3} = \frac{15}{3} \ \Rightarrow\ x = 5 \]
\[ 3\cdot5 + 2 = 15 + 2 = 17 \checkmark \]Trying values of x in 3x + 2 = 17
| x | 3x + 2 | Equals 17? |
|---|---|---|
| 3 | 11 | no |
| 4 | 14 | no |
| 5 | 17 | yes |
| 6 | 20 | no |
| 7 | 23 | no |
Questions
What is x in 3x + 2 = 17?
The solution of 3x + 2 = 17 is x = 5.
How do you solve 3x + 2 = 17?
Subtract 2 from both sides to get 3x = 15, then divide both sides by 3 to get x = 5.
How do I check the answer?
Replace x by 5: 3(5) + 2 = 17, which is 17.