Solve 3x + 15 = ā3
The solution of 3x + 15 = ā3 is x = -6.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 15 from both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = -6 back into the equation.
LaTeX source of the formulas on this page
\[ 3x + 15 = -3\ \Rightarrow\ x = -6 \]
\[ 3x + 15 = -3 \]
\[ 3x + 15 - 15 = -3 - 15 \ \Rightarrow\ 3x = -18 \]
\[ \frac{3x}{3} = \frac{-18}{3} \ \Rightarrow\ x = -6 \]
\[ 3\cdot(-6) + 15 = -18 + 15 = -3 \checkmark \]Trying values of x in 3x + 15 = ā3
| x | 3x + 15 | Equals -3? |
|---|---|---|
| -8 | -9 | no |
| -7 | -6 | no |
| -6 | -3 | yes |
| -5 | 0 | no |
| -4 | 3 | no |
Questions
What is x in 3x + 15 = ā3?
The solution of 3x + 15 = ā3 is x = -6.
How do you solve 3x + 15 = ā3?
Subtract 15 from both sides to get 3x = -18, then divide both sides by 3 to get x = -6.
How do I check the answer?
Replace x by -6: 3(-6) + 15 = -3, which is -3.