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Solve 3x + 13 = āˆ’2

The solution of 3x + 13 = āˆ’2 is x = -5.

The lines y = 3x + 13 and y = -2 meet at x = -5-10-8-6-4-2-20-15-10-551015x = -5y = 3x + 13y = -2
The lines y = 3x + 13 and y = -2 meet at x = -5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    3x+13=āˆ’23x + 13 = -2
  2. 2

    Subtract 13 from both sides:

    3x+13āˆ’13=āˆ’2āˆ’13 ⇒ 3x=āˆ’153x + 13 - 13 = -2 - 13 \ \Rightarrow\ 3x = -15
  3. 3

    Divide both sides by 3:

    3x3=āˆ’153 ⇒ x=āˆ’5\frac{3x}{3} = \frac{-15}{3} \ \Rightarrow\ x = -5
  4. 4

    Check: put x = -5 back into the equation.

    3ā‹…(āˆ’5)+13=āˆ’15+13=āˆ’2āœ“3\cdot(-5) + 13 = -15 + 13 = -2 \checkmark
LaTeX source of the formulas on this page
\[ 3x + 13 = -2\ \Rightarrow\ x = -5 \]
\[ 3x + 13 = -2 \]
\[ 3x + 13 - 13 = -2 - 13 \ \Rightarrow\ 3x = -15 \]
\[ \frac{3x}{3} = \frac{-15}{3} \ \Rightarrow\ x = -5 \]
\[ 3\cdot(-5) + 13 = -15 + 13 = -2 \checkmark \]

Trying values of x in 3x + 13 = āˆ’2

x3x + 13Equals -2?
-7-8no
-6-5no
-5-2yes
-41no
-34no

Questions

What is x in 3x + 13 = āˆ’2?

The solution of 3x + 13 = āˆ’2 is x = -5.

How do you solve 3x + 13 = āˆ’2?

Subtract 13 from both sides to get 3x = -15, then divide both sides by 3 to get x = -5.

How do I check the answer?

Replace x by -5: 3(-5) + 13 = -2, which is -2.

Similar equations

    Solve 3x + 13 = āˆ’2: x = -5 (steps and check) | WordGPT