Solve 3x + 13 = ā2
The solution of 3x + 13 = ā2 is x = -5.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 13 from both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = -5 back into the equation.
LaTeX source of the formulas on this page
\[ 3x + 13 = -2\ \Rightarrow\ x = -5 \]
\[ 3x + 13 = -2 \]
\[ 3x + 13 - 13 = -2 - 13 \ \Rightarrow\ 3x = -15 \]
\[ \frac{3x}{3} = \frac{-15}{3} \ \Rightarrow\ x = -5 \]
\[ 3\cdot(-5) + 13 = -15 + 13 = -2 \checkmark \]Trying values of x in 3x + 13 = ā2
| x | 3x + 13 | Equals -2? |
|---|---|---|
| -7 | -8 | no |
| -6 | -5 | no |
| -5 | -2 | yes |
| -4 | 1 | no |
| -3 | 4 | no |
Questions
What is x in 3x + 13 = ā2?
The solution of 3x + 13 = ā2 is x = -5.
How do you solve 3x + 13 = ā2?
Subtract 13 from both sides to get 3x = -15, then divide both sides by 3 to get x = -5.
How do I check the answer?
Replace x by -5: 3(-5) + 13 = -2, which is -2.