Solve 3x + 13 = 4
The solution of 3x + 13 = 4 is x = -3.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 13 from both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = -3 back into the equation.
LaTeX source of the formulas on this page
\[ 3x + 13 = 4\ \Rightarrow\ x = -3 \]
\[ 3x + 13 = 4 \]
\[ 3x + 13 - 13 = 4 - 13 \ \Rightarrow\ 3x = -9 \]
\[ \frac{3x}{3} = \frac{-9}{3} \ \Rightarrow\ x = -3 \]
\[ 3\cdot(-3) + 13 = -9 + 13 = 4 \checkmark \]Trying values of x in 3x + 13 = 4
| x | 3x + 13 | Equals 4? |
|---|---|---|
| -5 | -2 | no |
| -4 | 1 | no |
| -3 | 4 | yes |
| -2 | 7 | no |
| -1 | 10 | no |
Questions
What is x in 3x + 13 = 4?
The solution of 3x + 13 = 4 is x = -3.
How do you solve 3x + 13 = 4?
Subtract 13 from both sides to get 3x = -9, then divide both sides by 3 to get x = -3.
How do I check the answer?
Replace x by -3: 3(-3) + 13 = 4, which is 4.