Solve 3x + 12 = ā15
The solution of 3x + 12 = ā15 is x = -9.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 12 from both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = -9 back into the equation.
LaTeX source of the formulas on this page
\[ 3x + 12 = -15\ \Rightarrow\ x = -9 \]
\[ 3x + 12 = -15 \]
\[ 3x + 12 - 12 = -15 - 12 \ \Rightarrow\ 3x = -27 \]
\[ \frac{3x}{3} = \frac{-27}{3} \ \Rightarrow\ x = -9 \]
\[ 3\cdot(-9) + 12 = -27 + 12 = -15 \checkmark \]Trying values of x in 3x + 12 = ā15
| x | 3x + 12 | Equals -15? |
|---|---|---|
| -11 | -21 | no |
| -10 | -18 | no |
| -9 | -15 | yes |
| -8 | -12 | no |
| -7 | -9 | no |
Questions
What is x in 3x + 12 = ā15?
The solution of 3x + 12 = ā15 is x = -9.
How do you solve 3x + 12 = ā15?
Subtract 12 from both sides to get 3x = -27, then divide both sides by 3 to get x = -9.
How do I check the answer?
Replace x by -9: 3(-9) + 12 = -15, which is -15.