Solve 3x + 11 = ā4
The solution of 3x + 11 = ā4 is x = -5.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 11 from both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = -5 back into the equation.
LaTeX source of the formulas on this page
\[ 3x + 11 = -4\ \Rightarrow\ x = -5 \]
\[ 3x + 11 = -4 \]
\[ 3x + 11 - 11 = -4 - 11 \ \Rightarrow\ 3x = -15 \]
\[ \frac{3x}{3} = \frac{-15}{3} \ \Rightarrow\ x = -5 \]
\[ 3\cdot(-5) + 11 = -15 + 11 = -4 \checkmark \]Trying values of x in 3x + 11 = ā4
| x | 3x + 11 | Equals -4? |
|---|---|---|
| -7 | -10 | no |
| -6 | -7 | no |
| -5 | -4 | yes |
| -4 | -1 | no |
| -3 | 2 | no |
Questions
What is x in 3x + 11 = ā4?
The solution of 3x + 11 = ā4 is x = -5.
How do you solve 3x + 11 = ā4?
Subtract 11 from both sides to get 3x = -15, then divide both sides by 3 to get x = -5.
How do I check the answer?
Replace x by -5: 3(-5) + 11 = -4, which is -4.