Solve 3x + 11 = ā16
The solution of 3x + 11 = ā16 is x = -9.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 11 from both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = -9 back into the equation.
LaTeX source of the formulas on this page
\[ 3x + 11 = -16\ \Rightarrow\ x = -9 \]
\[ 3x + 11 = -16 \]
\[ 3x + 11 - 11 = -16 - 11 \ \Rightarrow\ 3x = -27 \]
\[ \frac{3x}{3} = \frac{-27}{3} \ \Rightarrow\ x = -9 \]
\[ 3\cdot(-9) + 11 = -27 + 11 = -16 \checkmark \]Trying values of x in 3x + 11 = ā16
| x | 3x + 11 | Equals -16? |
|---|---|---|
| -11 | -22 | no |
| -10 | -19 | no |
| -9 | -16 | yes |
| -8 | -13 | no |
| -7 | -10 | no |
Questions
What is x in 3x + 11 = ā16?
The solution of 3x + 11 = ā16 is x = -9.
How do you solve 3x + 11 = ā16?
Subtract 11 from both sides to get 3x = -27, then divide both sides by 3 to get x = -9.
How do I check the answer?
Replace x by -9: 3(-9) + 11 = -16, which is -16.