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Solve 3x + 1 = āˆ’11

The solution of 3x + 1 = āˆ’11 is x = -4.

The lines y = 3x + 1 and y = -11 meet at x = -4-10-8-6-4-22-30-25-20-15-10-5510x = -4y = 3x + 1y = -11
The lines y = 3x + 1 and y = -11 meet at x = -4. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    3x+1=āˆ’113x + 1 = -11
  2. 2

    Subtract 1 from both sides:

    3x+1āˆ’1=āˆ’11āˆ’1 ⇒ 3x=āˆ’123x + 1 - 1 = -11 - 1 \ \Rightarrow\ 3x = -12
  3. 3

    Divide both sides by 3:

    3x3=āˆ’123 ⇒ x=āˆ’4\frac{3x}{3} = \frac{-12}{3} \ \Rightarrow\ x = -4
  4. 4

    Check: put x = -4 back into the equation.

    3ā‹…(āˆ’4)+1=āˆ’12+1=āˆ’11āœ“3\cdot(-4) + 1 = -12 + 1 = -11 \checkmark
LaTeX source of the formulas on this page
\[ 3x + 1 = -11\ \Rightarrow\ x = -4 \]
\[ 3x + 1 = -11 \]
\[ 3x + 1 - 1 = -11 - 1 \ \Rightarrow\ 3x = -12 \]
\[ \frac{3x}{3} = \frac{-12}{3} \ \Rightarrow\ x = -4 \]
\[ 3\cdot(-4) + 1 = -12 + 1 = -11 \checkmark \]

Trying values of x in 3x + 1 = āˆ’11

x3x + 1Equals -11?
-6-17no
-5-14no
-4-11yes
-3-8no
-2-5no

Questions

What is x in 3x + 1 = āˆ’11?

The solution of 3x + 1 = āˆ’11 is x = -4.

How do you solve 3x + 1 = āˆ’11?

Subtract 1 from both sides to get 3x = -12, then divide both sides by 3 to get x = -4.

How do I check the answer?

Replace x by -4: 3(-4) + 1 = -11, which is -11.

Similar equations

    Solve 3x + 1 = āˆ’11: x = -4 (steps and check) | WordGPT