Solve 3x + 1 = ā11
The solution of 3x + 1 = ā11 is x = -4.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = -4 back into the equation.
LaTeX source of the formulas on this page
\[ 3x + 1 = -11\ \Rightarrow\ x = -4 \]
\[ 3x + 1 = -11 \]
\[ 3x + 1 - 1 = -11 - 1 \ \Rightarrow\ 3x = -12 \]
\[ \frac{3x}{3} = \frac{-12}{3} \ \Rightarrow\ x = -4 \]
\[ 3\cdot(-4) + 1 = -12 + 1 = -11 \checkmark \]Trying values of x in 3x + 1 = ā11
| x | 3x + 1 | Equals -11? |
|---|---|---|
| -6 | -17 | no |
| -5 | -14 | no |
| -4 | -11 | yes |
| -3 | -8 | no |
| -2 | -5 | no |
Questions
What is x in 3x + 1 = ā11?
The solution of 3x + 1 = ā11 is x = -4.
How do you solve 3x + 1 = ā11?
Subtract 1 from both sides to get 3x = -12, then divide both sides by 3 to get x = -4.
How do I check the answer?
Replace x by -4: 3(-4) + 1 = -11, which is -11.