Solve 3x ā 7 = 38
The solution of 3x ā 7 = 38 is x = 15.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 7 to both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = 15 back into the equation.
LaTeX source of the formulas on this page
\[ 3x - 7 = 38\ \Rightarrow\ x = 15 \]
\[ 3x - 7 = 38 \]
\[ 3x - 7 + 7 = 38 + 7 \ \Rightarrow\ 3x = 45 \]
\[ \frac{3x}{3} = \frac{45}{3} \ \Rightarrow\ x = 15 \]
\[ 3\cdot15 - 7 = 45 - 7 = 38 \checkmark \]Trying values of x in 3x ā 7 = 38
| x | 3x ā 7 | Equals 38? |
|---|---|---|
| 13 | 32 | no |
| 14 | 35 | no |
| 15 | 38 | yes |
| 16 | 41 | no |
| 17 | 44 | no |
Questions
What is x in 3x ā 7 = 38?
The solution of 3x ā 7 = 38 is x = 15.
How do you solve 3x ā 7 = 38?
Add 7 to both sides to get 3x = 45, then divide both sides by 3 to get x = 15.
How do I check the answer?
Replace x by 15: 3(15) ā 7 = 38, which is 38.