Solve 3x ā 7 = 32
The solution of 3x ā 7 = 32 is x = 13.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 7 to both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = 13 back into the equation.
LaTeX source of the formulas on this page
\[ 3x - 7 = 32\ \Rightarrow\ x = 13 \]
\[ 3x - 7 = 32 \]
\[ 3x - 7 + 7 = 32 + 7 \ \Rightarrow\ 3x = 39 \]
\[ \frac{3x}{3} = \frac{39}{3} \ \Rightarrow\ x = 13 \]
\[ 3\cdot13 - 7 = 39 - 7 = 32 \checkmark \]Trying values of x in 3x ā 7 = 32
| x | 3x ā 7 | Equals 32? |
|---|---|---|
| 11 | 26 | no |
| 12 | 29 | no |
| 13 | 32 | yes |
| 14 | 35 | no |
| 15 | 38 | no |
Questions
What is x in 3x ā 7 = 32?
The solution of 3x ā 7 = 32 is x = 13.
How do you solve 3x ā 7 = 32?
Add 7 to both sides to get 3x = 39, then divide both sides by 3 to get x = 13.
How do I check the answer?
Replace x by 13: 3(13) ā 7 = 32, which is 32.