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Solve 3x āˆ’ 7 = 32

The solution of 3x āˆ’ 7 = 32 is x = 13.

The lines y = 3x āˆ’ 7 and y = 32 meet at x = 13810121416181520253035404550x = 13y = 3x āˆ’ 7y = 32
The lines y = 3x āˆ’ 7 and y = 32 meet at x = 13. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    3xāˆ’7=323x - 7 = 32
  2. 2

    Add 7 to both sides:

    3xāˆ’7+7=32+7 ⇒ 3x=393x - 7 + 7 = 32 + 7 \ \Rightarrow\ 3x = 39
  3. 3

    Divide both sides by 3:

    3x3=393 ⇒ x=13\frac{3x}{3} = \frac{39}{3} \ \Rightarrow\ x = 13
  4. 4

    Check: put x = 13 back into the equation.

    3ā‹…13āˆ’7=39āˆ’7=32āœ“3\cdot13 - 7 = 39 - 7 = 32 \checkmark
LaTeX source of the formulas on this page
\[ 3x - 7 = 32\ \Rightarrow\ x = 13 \]
\[ 3x - 7 = 32 \]
\[ 3x - 7 + 7 = 32 + 7 \ \Rightarrow\ 3x = 39 \]
\[ \frac{3x}{3} = \frac{39}{3} \ \Rightarrow\ x = 13 \]
\[ 3\cdot13 - 7 = 39 - 7 = 32 \checkmark \]

Trying values of x in 3x āˆ’ 7 = 32

x3x āˆ’ 7Equals 32?
1126no
1229no
1332yes
1435no
1538no

Questions

What is x in 3x āˆ’ 7 = 32?

The solution of 3x āˆ’ 7 = 32 is x = 13.

How do you solve 3x āˆ’ 7 = 32?

Add 7 to both sides to get 3x = 39, then divide both sides by 3 to get x = 13.

How do I check the answer?

Replace x by 13: 3(13) āˆ’ 7 = 32, which is 32.

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