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Solve 3x āˆ’ 2 = 10

The solution of 3x āˆ’ 2 = 10 is x = 4.

The lines y = 3x āˆ’ 2 and y = 10 meet at x = 4-2246810-10-551015202530x = 4y = 3x āˆ’ 2y = 10
The lines y = 3x āˆ’ 2 and y = 10 meet at x = 4. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    3xāˆ’2=103x - 2 = 10
  2. 2

    Add 2 to both sides:

    3xāˆ’2+2=10+2 ⇒ 3x=123x - 2 + 2 = 10 + 2 \ \Rightarrow\ 3x = 12
  3. 3

    Divide both sides by 3:

    3x3=123 ⇒ x=4\frac{3x}{3} = \frac{12}{3} \ \Rightarrow\ x = 4
  4. 4

    Check: put x = 4 back into the equation.

    3ā‹…4āˆ’2=12āˆ’2=10āœ“3\cdot4 - 2 = 12 - 2 = 10 \checkmark
LaTeX source of the formulas on this page
\[ 3x - 2 = 10\ \Rightarrow\ x = 4 \]
\[ 3x - 2 = 10 \]
\[ 3x - 2 + 2 = 10 + 2 \ \Rightarrow\ 3x = 12 \]
\[ \frac{3x}{3} = \frac{12}{3} \ \Rightarrow\ x = 4 \]
\[ 3\cdot4 - 2 = 12 - 2 = 10 \checkmark \]

Trying values of x in 3x āˆ’ 2 = 10

x3x āˆ’ 2Equals 10?
24no
37no
410yes
513no
616no

Questions

What is x in 3x āˆ’ 2 = 10?

The solution of 3x āˆ’ 2 = 10 is x = 4.

How do you solve 3x āˆ’ 2 = 10?

Add 2 to both sides to get 3x = 12, then divide both sides by 3 to get x = 4.

How do I check the answer?

Replace x by 4: 3(4) āˆ’ 2 = 10, which is 10.

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