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Solve 3x āˆ’ 15 = āˆ’3

The solution of 3x āˆ’ 15 = āˆ’3 is x = 4.

The lines y = 3x āˆ’ 15 and y = -3 meet at x = 4-2246810-20-15-10-551015x = 4y = 3x āˆ’ 15y = -3
The lines y = 3x āˆ’ 15 and y = -3 meet at x = 4. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    3xāˆ’15=āˆ’33x - 15 = -3
  2. 2

    Add 15 to both sides:

    3xāˆ’15+15=āˆ’3+15 ⇒ 3x=123x - 15 + 15 = -3 + 15 \ \Rightarrow\ 3x = 12
  3. 3

    Divide both sides by 3:

    3x3=123 ⇒ x=4\frac{3x}{3} = \frac{12}{3} \ \Rightarrow\ x = 4
  4. 4

    Check: put x = 4 back into the equation.

    3ā‹…4āˆ’15=12āˆ’15=āˆ’3āœ“3\cdot4 - 15 = 12 - 15 = -3 \checkmark
LaTeX source of the formulas on this page
\[ 3x - 15 = -3\ \Rightarrow\ x = 4 \]
\[ 3x - 15 = -3 \]
\[ 3x - 15 + 15 = -3 + 15 \ \Rightarrow\ 3x = 12 \]
\[ \frac{3x}{3} = \frac{12}{3} \ \Rightarrow\ x = 4 \]
\[ 3\cdot4 - 15 = 12 - 15 = -3 \checkmark \]

Trying values of x in 3x āˆ’ 15 = āˆ’3

x3x āˆ’ 15Equals -3?
2-9no
3-6no
4-3yes
50no
63no

Questions

What is x in 3x āˆ’ 15 = āˆ’3?

The solution of 3x āˆ’ 15 = āˆ’3 is x = 4.

How do you solve 3x āˆ’ 15 = āˆ’3?

Add 15 to both sides to get 3x = 12, then divide both sides by 3 to get x = 4.

How do I check the answer?

Replace x by 4: 3(4) āˆ’ 15 = -3, which is -3.

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    Solve 3x āˆ’ 15 = āˆ’3: x = 4 (steps and check) | WordGPT