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Solve 3x āˆ’ 15 = āˆ’12

The solution of 3x āˆ’ 15 = āˆ’12 is x = 1.

The lines y = 3x āˆ’ 15 and y = -12 meet at x = 1-4-2246-30-25-20-15-10-55x = 1y = 3x āˆ’ 15y = -12
The lines y = 3x āˆ’ 15 and y = -12 meet at x = 1. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    3xāˆ’15=āˆ’123x - 15 = -12
  2. 2

    Add 15 to both sides:

    3xāˆ’15+15=āˆ’12+15 ⇒ 3x=33x - 15 + 15 = -12 + 15 \ \Rightarrow\ 3x = 3
  3. 3

    Divide both sides by 3:

    3x3=33 ⇒ x=1\frac{3x}{3} = \frac{3}{3} \ \Rightarrow\ x = 1
  4. 4

    Check: put x = 1 back into the equation.

    3ā‹…1āˆ’15=3āˆ’15=āˆ’12āœ“3\cdot1 - 15 = 3 - 15 = -12 \checkmark
LaTeX source of the formulas on this page
\[ 3x - 15 = -12\ \Rightarrow\ x = 1 \]
\[ 3x - 15 = -12 \]
\[ 3x - 15 + 15 = -12 + 15 \ \Rightarrow\ 3x = 3 \]
\[ \frac{3x}{3} = \frac{3}{3} \ \Rightarrow\ x = 1 \]
\[ 3\cdot1 - 15 = 3 - 15 = -12 \checkmark \]

Trying values of x in 3x āˆ’ 15 = āˆ’12

x3x āˆ’ 15Equals -12?
-1-18no
0-15no
1-12yes
2-9no
3-6no

Questions

What is x in 3x āˆ’ 15 = āˆ’12?

The solution of 3x āˆ’ 15 = āˆ’12 is x = 1.

How do you solve 3x āˆ’ 15 = āˆ’12?

Add 15 to both sides to get 3x = 3, then divide both sides by 3 to get x = 1.

How do I check the answer?

Replace x by 1: 3(1) āˆ’ 15 = -12, which is -12.

Similar equations

    Solve 3x āˆ’ 15 = āˆ’12: x = 1 (steps and check) | WordGPT