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Solve 3x āˆ’ 13 = 32

The solution of 3x āˆ’ 13 = 32 is x = 15.

The lines y = 3x āˆ’ 13 and y = 32 meet at x = 151012141618201520253035404550x = 15y = 3x āˆ’ 13y = 32
The lines y = 3x āˆ’ 13 and y = 32 meet at x = 15. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    3xāˆ’13=323x - 13 = 32
  2. 2

    Add 13 to both sides:

    3xāˆ’13+13=32+13 ⇒ 3x=453x - 13 + 13 = 32 + 13 \ \Rightarrow\ 3x = 45
  3. 3

    Divide both sides by 3:

    3x3=453 ⇒ x=15\frac{3x}{3} = \frac{45}{3} \ \Rightarrow\ x = 15
  4. 4

    Check: put x = 15 back into the equation.

    3ā‹…15āˆ’13=45āˆ’13=32āœ“3\cdot15 - 13 = 45 - 13 = 32 \checkmark
LaTeX source of the formulas on this page
\[ 3x - 13 = 32\ \Rightarrow\ x = 15 \]
\[ 3x - 13 = 32 \]
\[ 3x - 13 + 13 = 32 + 13 \ \Rightarrow\ 3x = 45 \]
\[ \frac{3x}{3} = \frac{45}{3} \ \Rightarrow\ x = 15 \]
\[ 3\cdot15 - 13 = 45 - 13 = 32 \checkmark \]

Trying values of x in 3x āˆ’ 13 = 32

x3x āˆ’ 13Equals 32?
1326no
1429no
1532yes
1635no
1738no

Questions

What is x in 3x āˆ’ 13 = 32?

The solution of 3x āˆ’ 13 = 32 is x = 15.

How do you solve 3x āˆ’ 13 = 32?

Add 13 to both sides to get 3x = 45, then divide both sides by 3 to get x = 15.

How do I check the answer?

Replace x by 15: 3(15) āˆ’ 13 = 32, which is 32.

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