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Solve 3x āˆ’ 13 = 20

The solution of 3x āˆ’ 13 = 20 is x = 11.

The lines y = 3x āˆ’ 13 and y = 20 meet at x = 116810121416510152025303540x = 11y = 3x āˆ’ 13y = 20
The lines y = 3x āˆ’ 13 and y = 20 meet at x = 11. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    3xāˆ’13=203x - 13 = 20
  2. 2

    Add 13 to both sides:

    3xāˆ’13+13=20+13 ⇒ 3x=333x - 13 + 13 = 20 + 13 \ \Rightarrow\ 3x = 33
  3. 3

    Divide both sides by 3:

    3x3=333 ⇒ x=11\frac{3x}{3} = \frac{33}{3} \ \Rightarrow\ x = 11
  4. 4

    Check: put x = 11 back into the equation.

    3ā‹…11āˆ’13=33āˆ’13=20āœ“3\cdot11 - 13 = 33 - 13 = 20 \checkmark
LaTeX source of the formulas on this page
\[ 3x - 13 = 20\ \Rightarrow\ x = 11 \]
\[ 3x - 13 = 20 \]
\[ 3x - 13 + 13 = 20 + 13 \ \Rightarrow\ 3x = 33 \]
\[ \frac{3x}{3} = \frac{33}{3} \ \Rightarrow\ x = 11 \]
\[ 3\cdot11 - 13 = 33 - 13 = 20 \checkmark \]

Trying values of x in 3x āˆ’ 13 = 20

x3x āˆ’ 13Equals 20?
914no
1017no
1120yes
1223no
1326no

Questions

What is x in 3x āˆ’ 13 = 20?

The solution of 3x āˆ’ 13 = 20 is x = 11.

How do you solve 3x āˆ’ 13 = 20?

Add 13 to both sides to get 3x = 33, then divide both sides by 3 to get x = 11.

How do I check the answer?

Replace x by 11: 3(11) āˆ’ 13 = 20, which is 20.

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